在小於等於限制的情況下一直遞迴找能放入的數字,並不斷刷新Maxsum(最接近限制的和),詳細看底下。
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#include <cstdio> | |
#include <vector> | |
using namespace std; | |
int track[21]; | |
int N, T; // T is number of tracks | |
vector<int> Container; // 遞迴時暫存track | |
vector<int> Ans; | |
int Maxsum; | |
void combination(int pos, int sum); | |
int main() | |
{ | |
while (scanf("%d %d", &N, &T) != EOF) { | |
for (int i = 0; i < T; ++i) | |
scanf("%d", &track[i]); | |
Container.clear(); | |
Maxsum = 0; | |
combination(0, 0); | |
int sum = 0; | |
for (int n : Ans) { | |
printf("%d ", n); | |
sum += n; | |
} | |
printf("sum:%d\n", sum); | |
} | |
} | |
void combination(int pos, int sum) | |
{ | |
if (sum > Maxsum) { // 不斷刷新Maxsum,使得Maxsum更接近N | |
Ans = Container; | |
Maxsum = sum; | |
} | |
for (int i = pos; i < T; ++i) { | |
if (track[i] + sum <= N) { | |
sum += track[i]; | |
Container.push_back(track[i]); | |
combination(i + 1, sum); | |
sum -= track[i]; | |
Container.pop_back(); | |
} | |
} | |
} |
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