透過遞迴求出答案。
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#include <cstdio> | |
using namespace std; | |
void bangla(long long int n) | |
{ | |
if (n >= 10000000){ | |
bangla (n / 10000000); | |
printf (" kuti"); | |
n %= 10000000; | |
} | |
if (n >= 100000){ | |
bangla (n / 100000); | |
printf (" lakh"); | |
n %= 100000; | |
} | |
if (n >= 1000){ | |
bangla (n / 1000); | |
printf (" hajar"); | |
n %= 1000; | |
} | |
if (n >= 100){ | |
bangla (n / 100); | |
printf (" shata"); | |
n %= 100; | |
} | |
if (n) | |
printf (" %d",n); | |
} | |
int main() | |
{ | |
long long int n; | |
int Case=1; | |
while (scanf("%lld",&n)!=EOF){ | |
printf ("%4d.",Case++); | |
if (n==0) printf(" 0"); | |
bangla (n); | |
printf("\n"); | |
} | |
return 0; | |
} |
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